HDU 4511
SHIT,SHIT,SHIT,SHIT,SHIT...
这道题可以使用AC自动机+DP来解决。也就是用非法路径建立TRIE图,然后从trie[root][1]点开始广搜DP即可。千万要注意一点,题目里有说:小明每次走的时候只能走到比当前所在点编号大的位置
因为这个WA了无限次。。。
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <vector>
#define LL __int64
using namespace std;
const int N=25000;
const int root=0;
int trie[N][55];
int fail[N];
bool tag[N];
int que[N],head,tail,tot;
int n,m;
double dp[550][55],d[55][55];
struct Point{
double x,y;
}point[55];
void init(){
for(int i=0;i<=549;i++){
for(int j=0;j<=50;j++)
dp[i][j]=1e20;
}
head=tail=tot=0;
memset(fail,-1,sizeof(fail));
memset(tag,false,sizeof(tag));
}
double dist(int i,int j){
return sqrt((point[i].x-point[j].x)*(point[i].x-point[j].x)+(point[i].y-point[j].y)*(point[i].y-point[j].y));
}
int sthead,stail;
struct Stat{
int pos_in_trie,pos;
Stat(){};
Stat(int a,int b){ pos_in_trie=a,pos=b; }
}stque[N*10];
void clr(int p){
memset(trie[p],-1,sizeof(trie[p]));
}
void build_ac(){
head=tail=0;
que[tail++]=root;
while(head!=tail){
int tmp=que[head++];
int p=-1;
for(int i=1;i<=n;i++){
if(trie[tmp][i]!=-1){
if(tmp==root) fail[trie[tmp][i]]=root;
else{
p=fail[tmp];
while(p!=-1){
if(trie[p][i]!=-1){
fail[trie[tmp][i]]=trie[p][i];
break;
}
p=fail[p];
}
if(p==-1) fail[trie[tmp][i]]=root;
}
if(tag[fail[trie[tmp][i]]]) tag[trie[tmp][i]]=tag[fail[trie[tmp][i]]];
que[tail++]=trie[tmp][i];
}
else{ //trie[tmp][i]==-1
if(tmp==root) trie[tmp][i]=root;
else{
p=fail[tmp];
while(p!=-1){
if(trie[p][i]!=-1){
trie[tmp][i]=trie[p][i];
break;
}
p=fail[p];
}
if(p==-1) trie[tmp][i]=root;
}
}
}
}
}
void BFS(){
Stat tmp;
while(sthead<stail){
tmp=stque[sthead++];
for(int i=tmp.pos;i<=n;i++){
if(!tag[trie[tmp.pos_in_trie][i]]){
if(dp[trie[tmp.pos_in_trie][i]][i]>dp[tmp.pos_in_trie][tmp.pos]+d[i][tmp.pos]){
dp[trie[tmp.pos_in_trie][i]][i]=dp[tmp.pos_in_trie][tmp.pos]+d[i][tmp.pos];
stque[stail++]=Stat(trie[tmp.pos_in_trie][i],i);
}
}
}
}
}
int main(){
int k;
while(scanf("%d%d",&n,&m),n||m){
init();
for(int i=1;i<=n;i++)
scanf("%lf%lf",&point[i].x,&point[i].y);
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++)
d[i][j]=dist(i,j);
}
int p,tmp;
clr(0);
for(int i=1;i<=m;i++){
scanf("%d",&k);
p=0;
for(int j=1;j<=k;j++){
scanf("%d",&tmp);
if(trie[p][tmp]==-1){
clr(++tot);
trie[p][tmp]=tot;
}
p=trie[p][tmp];
}
tag[p]=true;
}
build_ac();
sthead=stail=0;
dp[trie[root][1]][1]=0;
stque[stail++]=Stat(trie[root][1],1);
BFS();
double ans=1e20;
for(int i=0;i<550;i++)
ans=min(ans,dp[i][n]);
if(ans==1e20)
printf("Can not be reached!\n");
else printf("%.2lf\n",ans);
}
return 0;
}

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