poj 1635

有根树同构。参考论文《hash在。。。。》

 1 #include <iostream>
 2 #include <fstream>
 3 #include <algorithm>
 4 #include <cstring>
 5 #include <climits>
 6 #include <cmath>
 7 
 8 using namespace std;
 9 
10 const int leaf_hash=2099;
11 const int pt=9323;
12 const int qt=8719;
13 char str1[3100], str2[3100];
14 char *p;
15 
16 int Hash()
17 {
18     int sum=1;
19     if(*(p)=='1'&&*(p-1)=='0'){
20         p++;
21         //cout<<"leaf_hash="<<endl;
22         return leaf_hash;
23     }
24     while(*p!='\0' && *p++ == '0')//这个巧妙的循环,把子节点的hash值都加给了父节点,作为父节点的hash值
25     {
26         //cout<<"for"<<endl;
27         sum = (sum*(pt^Hash()))%qt;
28     }
29 //    printf("sum==%d\n",sum);
30     return sum;
31 }
32 
33 
34 int main()
35 {
36 //    freopen("input.txt", "r", stdin);
37     int T;
38     scanf("%d", &T);
39     while(T--)
40     {
41         scanf("%s%s", str1, str2);
42         p = str1;
43         int a = Hash();
44         p = str2;
45         //cout<<a<<endl;
46         int b = Hash();
47         //cout<<b<<endl;
48         if(a == b)
49         {
50             puts("same");
51         }
52         else
53         {
54             puts("different");
55         }
56     }
57     return 0;
58 }
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posted @ 2014-05-31 16:35  chenjunjie1994  阅读(216)  评论(0编辑  收藏  举报