[每日一题] OCP1z0-047 :2013-07-29 视图――别名
 
 
 
本题的考点是如何创建视图,对于视图的详细知识点,可以参考我的博客:
http://blog.csdn.net/guoyjoe/article/details/8614677
好,接下来我们来做测试,先登录到oe用户,查相关的表。
gyj@OCM> conn oe/oe Connected. oe@OCM> select table_name from tabs; TABLE_NAME ------------------------------ PRODUCT_REF_LIST_NESTEDTAB SUBCATEGORY_REF_LIST_NESTEDTAB PROMOTIONS ORDERS PRODUCT_DESCRIPTIONS WAREHOUSES PRODUCT_INFORMATION ORDER_ITEMS CUSTOMERS INVENTORIES 10 rows selected.
一、答案A,很明显是错的,视图的字段与表的字段的个数不一样,操作如下报错:
 
oe@OCM> CREATE OR REPLACE VIEW ord_vu(order_id,order_date) 
  2  AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
  3  GROUP BY o.order_id,o.order_date;
CREATE OR REPLACE VIEW ord_vu(order_id,order_date)
                              *
ERROR at line 1:
ORA-01730: invalid number of column names specified
在CREATE OR REPLACE VIEW ord_vu(order_id,order_date,ct)添加一列CT,操作如下就没问题:
oe@OCM> CREATE OR REPLACE VIEW ord_vu(order_id,order_date,ct) 
  2  AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
  3  GROUP BY o.order_id,o.order_date;
View created.
 
 
二、答案B是正确的,把视图定义的列名去掉,视图默认这些列名来自select中的显示的列,操作如下:
oe@OCM> CREATE OR REPLACE VIEW ord_vu 
  2  AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
  3  GROUP BY o.order_id,o.order_date;
View created.
oe@OCM> select * from ord_vu;
  ORDER_ID ORDER_DATE                                                                  NO OF ITEMS
---------- --------------------------------------------------------------------------- -----------
      2354 15-JUL-08 08.18.23.234567 AM                                                         13
      2361 14-NOV-07 05.34.21.986210 AM                                                          9
      2363 24-OCT-07 07.49.56.346122 AM                                                          9
      2367 28-JUN-08 11.53.32.335522 AM                                                          8
省略结果。。。。。。。。。。。。。。。
 
 
 
三、答案C是错的,在创建视图时,对这种使用各种函数,或运算表达式的列,一定要起别名,如没有别名视图创建就会失败,操作如下:
 
oe@OCM> CREATE OR REPLACE VIEW ord_vu 
  2  AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id) FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
  3  GROUP BY o.order_id,o.order_date;
AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id) FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
                                  *
ERROR at line 2:
ORA-00998: must name this expression with a column alias
把上面的视图改成如下:
oe@OCM> CREATE OR REPLACE VIEW ord_vu 
  2  AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id)  CT FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
  3  GROUP BY o.order_id,o.order_date;
View created.
 
 
 
oe@OCM> CREATE OR REPLACE VIEW ord_vu 
  2  AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id)||'NO OF ITEMS' FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
  3  GROUP BY o.order_id,o.order_date
  4  WITH CHECK OPTION;
AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id)||'NO OF ITEMS' FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
                                                        *
ERROR at line 2:
ORA-00998: must name this expression with a column alias
 把上面的视图改成如下:
oe@OCM> CREATE OR REPLACE VIEW ord_vu 
  2  AS SELECT o.order_id,o.order_date,COUNT(i.line_item_id)||'NO OF ITEMS' CT FROM orders o JOIN order_items i ON(o.order_id=i.order_id)
  3  GROUP BY o.order_id,o.order_date
  4  WITH CHECK OPTION;
View created.
 
 
结总:
在创建视图时,对这种使用各种函数,或运算表达式的列,一定要起别名,如没有别名视图创建就会失败。
定义视图的列名可以省略,来自SELECT定义中的列名,如果定义视图的列名不省略,那个列的个数与SELECT定义中的列的个数要一致。
 
 
 
 
                     
                    
                 
                    
                
 
                
            
         
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浙公网安备 33010602011771号