2020年3月16日python学习笔记——详细列表解说
坚持+思考+输出
1、学习方式:查看提供视频(30分钟)+自我整理笔记(2小时)+周末视频输出
2、笔记方式按提问方式整理。
# name = ["like","love","love","good"]
# n2 = ["test","hebing"]
#print(dir(name))
# 'append', 'clear', 'copy', 'count', 'extend', 'index', 'insert', 'pop', 'remove', 'reverse', 'sort'
#列表的增加操作
# name.append("插入最后") #添加到最后
# print(name)
#
# name.insert(1,"插入指定位置")
# print(name)
#
# name.extend(n2)#把n2插入到name列表里面
# print(name)
#
# name.insert(2,[1,2,3]) #列表嵌套
# print(name)
name = ["like","love","love","good"]
# n2 = ["test","hebing"]
#删除
# del name[0] #删除指定元素
# print(name)
#
# name.pop() #默认删除最后一个元素并返回被删除的值
# print(name)
#
# name.pop(1)#删除指定元素
# print(name)
#
# n2.clear() #直接删除
# print(n2)
name.remove("like") #直接移出元素
print(name)
# 查操作
# name = ["like","love","love","good","like"]
# n2 = ["test","hebing"]
#
# print(name.index("love"))#返回从左开始匹配到的第一个like的索引
#
# print(name.count("like")) #返回like的个数
#切片
# name = ["like","love","love","good","like"]
# n2 = ["test","hebing"]
#
# print(name[1:7])# 切片的特性是顾头不顾尾,即start的元素会被包含,end-1是实际取出来的值
#
# print(name[1:7:2])# 步长, 允许跳着取值
#
# print(name[::-1])#通过把步长设置成负值,可达到列表返转的效果['like', 'good', 'love', 'love', 'like']
# 排序&反转
# 排序
a = [83,4,2,4,6,19,33,21] #从小到大进行排序
# a.sort()
# print(a)
# 反转
# a.reverse()
# print(a)
# print(a[::-1])
# 循环列表
name = ["like","love","love","good","like"]
for i in name:
print(i)
posted on 2020-03-16 20:48 坚持是多么伟大的事情 阅读(173) 评论(0) 收藏 举报
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