分解字符串包含的信息值后然后合并到另外一表的信息(转)

分解字符串包含的信息值后然后合并到另外一表的信息

/*问题描述

tba

ID classid   name

tbb 1     1,2,3   西服 2     2,3     中山装3     1,3     名裤

id   classname

1     衣服

2     上衣

3    

 

我得的结果是

id   classname            name

1     衣服,上衣,裤子      西服

2     上衣,裤子          中山装

3     衣服,裤子          名裤

*/

 

-----------------------------------------------------

--sql server 2000中的写法

create table tba(ID int,classid varchar(20),name varchar(10))

insert into tba values(1,'1,2,3','西服')

insert into tba values(2,'2,3' ,'中山装')

insert into tba values(3,'1,3' ,'名裤')

create table tbb(ID varchar(10), classname varchar(10))

insert into tbb values('1','衣服')

insert into tbb values('2','上衣')

insert into tbb values('3','裤子')

go

 

--第1种方法,创建函数来显示

create function f_hb(@id varchar(10))

returns varchar(1000)

as

begin

 declare @str varchar(1000)

 set @str=''

 select @str=@str+','+[classname] from tbb where charindex(','+cast(id as varchar)+',',','+@id+',')>0

 return stuff(@str,1,1,'')

end

go

select id,classid=dbo.f_hb(classid),name from tba

drop function f_hb

/*

id          classid       name      

----------- ------------- ----------

1           衣服,上衣,裤子 西服

2           上衣,裤子      中山装

3           衣服,裤子      名裤

(所影响的行数为 3 行)

*/

 

--第2种方法.update

while(exists (select * from tba,tbb where charindex(tbb.id,tba.classid) >0))

update tba

set classid= replace(classid,tbb.id,tbb.classname)

from tbb

where charindex(tbb.id,tba.classid)>0

select * from tba

/*

ID          classid              name      

----------- -------------------- ----------

1           衣服,上衣,裤子       西服

2           上衣,裤子            中山装

3           衣服,裤子            名裤

(所影响的行数为 3 行)

*/

drop table tba,tbb

 

------------------------------------------------------------------------

--sql server 2005中先分解tba中的classid,然后再合并classname

create table tba(ID int,classid varchar(20),name varchar(10))

insert into tba values(1,'1,2,3','西服')

insert into tba values(2,'2,3' ,'中山装')

insert into tba values(3,'1,3' ,'名裤')

create table tbb(ID varchar(10), classname varchar(10))

insert into tbb values('1','衣服')

insert into tbb values('2','上衣')

insert into tbb values('3','裤子')

go

 

SELECT id , classname , name FROM

(

 SELECT DISTINCT id , name FROM (select tbc.id , tbc.name , tbb.classname from

  (

    SELECT A.id , A.name , B.classid FROM(SELECT id , name , [classid] = CONVERT(xml,'<root><v>' + REPLACE([classid], ',', '</v><v>') + '</v></root>') FROM tba)A

    OUTER APPLY(SELECT classid = N.v.value('.', 'varchar(100)') FROM A.[classid].nodes('/root/v') N(v))B

 ) tbc , tbb where tbc.classid = tbb.id

 ) T

)A

OUTER APPLY

(

 SELECT [classname]= STUFF(REPLACE(REPLACE((

    SELECT classname FROM (select tbc.id , tbc.name , tbb.classname from

    (

      SELECT A.id , A.name , B.classid FROM(SELECT id , name , [classid] = CONVERT(xml,'<root><v>' + REPLACE([classid], ',', '</v><v>') + '</v></root>') FROM tba)A

      OUTER APPLY(SELECT classid = N.v.value('.', 'varchar(100)') FROM A.[classid].nodes('/root/v') N(v))B

    ) tbc , tbb where tbc.classid = tbb.id

 ) N

 WHERE id = A.id and name = A.name

 FOR XML AUTO), '<N classname="', ','), '"/>', ''), 1, 1, '')

)N

order by id

 

drop table tba,tbb

 

/*

id          classname      name

----------- -------------- ----------

1           衣服,上衣,裤子 西服

2           上衣,裤子      中山装

3           衣服,裤子      名裤

(3 行受影响)

*/


posted @ 2011-08-08 16:53  佳园  阅读(488)  评论(0编辑  收藏  举报