摘要:
#include long gettime() { timeval t; gettimeofday(&t, NULL); return 1000*t.tv_sec + t.tv_usec/1000; } 阅读全文
posted @ 2019-11-11 15:40
jhc888007
阅读(847)
评论(0)
推荐(0)
摘要:
参考文献: https://www.jb51.net/article/36422.htm https://blog.csdn.net/jxt1234and2010/article/details/88588208 https://blog.csdn.net/jxt1234and2010/articl 阅读全文
posted @ 2019-11-11 15:39
jhc888007
阅读(142)
评论(0)
推荐(0)
浙公网安备 33010602011771号