摘要: #include long gettime() { timeval t; gettimeofday(&t, NULL); return 1000*t.tv_sec + t.tv_usec/1000; } 阅读全文
posted @ 2019-11-11 15:40 jhc888007 阅读(852) 评论(0) 推荐(0)
摘要: 参考文献: https://www.jb51.net/article/36422.htm https://blog.csdn.net/jxt1234and2010/article/details/88588208 https://blog.csdn.net/jxt1234and2010/articl 阅读全文
posted @ 2019-11-11 15:39 jhc888007 阅读(142) 评论(0) 推荐(0)