【python】sort 排序

sort排序

from operator import itemgetter
a = [
	{'name':'小张', 'create_time':'2020-10-16 09:56'},
	{'name':'小王', 'create_time':'2020-10-16 09:57'},
	{'name':'小李', 'create_time':'2020-10-16 09:58'},
	{'name':'小赵', 'create_time':'2020-10-16 09:59'}
]
a.sort(key=itemgetter('create_time'), reverse=True)
print(a)
[
{'name': '小赵', 'create_time': '2020-10-16 09:59'}, 
{'name': '小李', 'create_time': '2020-10-16 09:58'}, 
{'name': '小王', 'create_time': '2020-10-16 09:57'},
{'name': '小张', 'create_time': '2020-10-16 09:56'}
]

sorted排序(不会修改原来变量)

import datetime
def get_timestamp(date):
    return datetime.datetime.strptime(date,"%Y-%m-%d %H:%M:%S").timestamp()

s1=['2021-07-13 04:00:00', '2021-07-13 05:00:00', '2021-07-13 06:00:00']
s=sorted(s1,key=lambda date: get_timestamp(date))
# 对字典排序, 先获取字典的键值并生成list列表, 再进行排序
>>> my_dict = {'a':300,'c':100,'b':200}
>>> list_1 = list(my_dict.items())
>>> list_1
[('a', 300), ('c', 100), ('b', 200)]

# 对字典按照key值进行排序,并返回排序后的新字典
>>> my_dict_sortbykey = dict(sorted(list_1,key = lambda x:x[0]))
>>> my_dict_sortbykey
{'a': 300, 'b': 200, 'c': 100}
posted @ 2022-09-06 12:13  是阿杰呀  阅读(53)  评论(0)    收藏  举报