【python】datetime 计算两个时间的时间差, 以 秒为单位
from datetime import datetime
time1 = datetime(2022,6,14,10)
time2 = datetime(2022,6,14,11)
seconds = (time2-time1).total_seconds() # 3600.0
seconds_1 = (time1-time2).total_seconds() # -3600.0
from datetime import datetime
time1 = datetime(2022,6,14,10)
time2 = datetime(2022,6,14,11)
seconds = (time2-time1).total_seconds() # 3600.0
seconds_1 = (time1-time2).total_seconds() # -3600.0