Given a binary tree, return the inorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3},
1
\
2
/
3
return [1,3,2].
不用解释。
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> inorderTraversal(TreeNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
vector<int> *v = new vector<int>();
Travel(root,v);
return *v;
}
void Travel(TreeNode *root,vector<int> * v)
{
if(root != NULL)
{
Travel(root->left,v);
v->push_back(root->val);
Travel(root->right,v);
}
}
};