Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
中序周游判断是否是排好序的即可。
1 /** 2 * Definition for binary tree 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 int tmp; 13 bool tag; 14 bool key; 15 bool isValidBST(TreeNode *root) { 16 // Start typing your C/C++ solution below 17 // DO NOT write int main() function 18 tag = false; 19 key = true; 20 check(root); 21 return key; 22 } 23 void check(TreeNode *root) 24 { 25 if(key == false) 26 return; 27 if(root == NULL) 28 return; 29 check(root->left); 30 if(tag == false) 31 { 32 tmp = root->val; 33 tag = true; 34 } 35 else 36 { 37 if(root->val <= tmp) 38 key = false; 39 else 40 tmp = root->val; 41 } 42 check(root->right); 43 } 44 };

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