MySQL 查询各科前三的数据

 

 

 

 方法一:

SELECT sc.*,c.`
Cname` ,COUNT(sc.C)
FROM sc
LEFT JOIN sc a
ON sc.C = a.C AND sc.score >= a.score
LEFT JOIN course c
ON sc.C = c.C
WHERE sc.C = c.C
GROUP BY
sc.C,sc.S,sc.score
HAVING COUNT(sc.C)>=4
ORDER BY a.C,a.score DESC

解析:

先copy 一个sc 表中的数据,与原sc 进行对比。统计每个score 大于其他数据的计数。再按sc.C,sc.S进行分组

SELECT sc.* ,COUNT(sc.C) 
FROM sc  
LEFT JOIN sc a
ON sc.C = a.C AND sc.score >= a.score
GROUP BY sc.C,sc.S

 

 可以看到,第一行数据的count计数为 6,由于我们要取每科前三名,sc表中共有student S编号7个,

自身不纳入count进行计数,则为6个需要取出前3--计数大于3的值

SELECT sc.* ,COUNT(sc.C) 
FROM sc  
LEFT JOIN sc a
ON sc.C = a.C AND sc.score >= a.score
GROUP BY
sc.C,sc.S,sc.score
HAVING COUNT(sc.C)>3
ORDER BY a.C,a.score DESC

方法二:

SELECT a.* FROM
sc a
WHERE
(SELECT COUNT(*)
FROM sc
WHERE sc.C =a.C
AND a.score<sc.score) <3
ORDER BY a.C,a.score DESC

解析:

与方法一同理,复制一个表进行count计数

posted @ 2020-01-13 10:18  jescs  阅读(4160)  评论(0编辑  收藏  举报