A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.
Now given an M x N matrix, return True if and only if the matrix is Toeplitz.
Example 1:
Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]] Output: True Explanation: 1234 5123 9512 In the above grid, the diagonals are "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]", and in each diagonal all elements are the same, so the answer is True.
Example 2:
Input: matrix = [[1,2],[2,2]] Output: False Explanation: The diagonal "[1, 2]" has different elements.
Note:
matrixwill be a 2D array of integers.matrixwill have a number of rows and columns in range[1, 20].matrix[i][j]will be integers in range[0, 99].
托普利茨矩阵
没什么说法,就是无脑遍历,如果下个对角不相等,就直接返回错误。
class Solution(object): def isToeplitzMatrix(self, matrix): """ :type matrix: List[List[int]] :rtype: bool """ m = len(matrix) n = len(matrix[0]) for i in range(m - 1): for j in range(n - 1): if matrix[i][j] != matrix[i+1][j+1]: return False return True
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