摘要: select *,dense_rank() over(partition by Is_J12,Email1 ORDER BY BudgetClass1 ASC) as J12_level, case when Watch_PJ='Watch' then dense_rank() over(parti 阅读全文
posted @ 2022-04-28 15:48 Jay_Zhao 阅读(118) 评论(0) 推荐(0)
摘要: 100.0*数量/sum(数量)over(partition by 编号) as 数量占比 阅读全文
posted @ 2021-01-08 00:17 Jay_Zhao 阅读(169) 评论(0) 推荐(0)