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poj 2348 Euclid's Game-----博弈

2012-05-22 14:13  java环境变量  阅读(249)  评论(0)    收藏  举报

Euclid's Game
Time Limit: 1000MS Memory Limit: 65536K
Total Submissions: 6030 Accepted: 2441

Description

Two players, Stan and Ollie, play, starting with two natural numbers. Stan, the first player, subtracts any positive multiple of the lesser of the two numbers from the greater of the two numbers, provided that the resulting number must be nonnegative. Then Ollie, the second player, does the same with the two resulting numbers, then Stan, etc., alternately, until one player is able to subtract a multiple of the lesser number from the greater to reach 0, and thereby wins. For example, the players may start with (25,7): 
         25 7

         11 7

          4 7

          4 3

          1 3

          1 0

an Stan wins.

Input

The input consists of a number of lines. Each line contains two positive integers giving the starting two numbers of the game. Stan always starts.

Output

For each line of input, output one line saying either Stan wins or Ollie wins assuming that both of them play perfectly. The last line of input contains two zeroes and should not be processed.

Sample Input

34 12
15 24
0 0

Sample Output

Stan wins
Ollie wins


题目 没难度, 但是被坑了,int型不够。  所以要 long long 。
题目大意:  每次可以 把两个数中 较大数 减去 较小数的 倍数   ,  两人轮流操作, 先到 0 的赢。

//Memory: 164 KB		Time: 0 MS
//Language: C++		Result: Accepted
#include<stdio.h>
#define LL long long
int main()
{
//	freopen("in.txt","r",stdin);
	LL m,n,t,ok;
	while(~scanf("%lld%lld",&m,&n) && (n||m))
	{
		ok=1;
		if(n>m)t=m,m=n,n=t;
		while(1)
		{
			if(m>=2*n) break;
			m-=n;
			if(n>m)t=m,m=n,n=t;
			if(!n) break;
			ok=(!ok);
		}
		if(ok) printf("Stan wins\n");
		else printf("Ollie wins\n");	
	}
	return 0;
}