摘要: [问题描述]urlStr = [NSString stringWithFormat:@"http://XXXXX%@",@"忍耐"]];url = [NSURLURLWithString:urlStr];在用+ (id)URLWithString:(NSString *)URLString新建的url 为nil出错[解决方法](NSString *)stringByAddingPercentEscapesUsingEncoding:(NSStringEncoding)encodingurlStr = [NSString stringWithFormat: 阅读全文
posted @ 2013-12-12 14:41 Jarhom宏 阅读(455) 评论(0) 推荐(0)