正则表达式匹配
摘要:1.匹配数值 1 string= '`2500' 2 re.findall(r"\d+\.?\d*",string) 输出结果:['2500'] 1 import re 2 def salary(x): 3 try: 4 if x == '元': 5 return 0 6 else: 7 retur
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posted @ 2021-06-07 15:56
posted @ 2021-06-07 15:56
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posted @ 2021-05-26 22:29
posted @ 2021-05-26 22:18