No.1003：Hangover

Hangover
Time Limit:1000MS  Memory Limit:10000K
Total Submit:15768 Accepted:6827

Description

How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.

 

Input
The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.

Output
For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples.

Sample Input

1.00
3.71
0.04
5.19
0.00

 

Sample Output

3 card(s)
61 card(s)
1 card(s)
273 card(s)

Java实现代码：

/**//*
 * Main.java
 *
 * Created on 2006年9月15日, 下午7:20
 *
 * To change this template, choose Tools | Template Manager
 * and open the template in the editor.
 */

/** *//**
 *
 * @author jailu
 */
import java.util.*;
public class Main {
    
    public static void main(String[] args) {
        Scanner cin = new Scanner(System.in);
        while (cin.hasNext())
        {
            String str = cin.next();
            if (str.equals("0.00"))
            {
                break;
            }
            double dbInput = Double.parseDouble(str);
            double dbTemp = 0;
            double i;
            for (i = 1;dbTemp < dbInput;i ++)
            {
                dbTemp = dbTemp + (1 / (i + 1));
            }
            System.out.println(((int)i - 1) + " card(s)");
        }
    }
    
}

评定结果：

Run ID	User	Problem	Result	Memory	Time	Language	Code Length	Submit Time
1587486	jailu	1003	Accepted	1276K	156MS	Java	0.61K	2006-09-15 19:47:29.0