知道某一天的日期和星期几，计算第n天后的日期以及是星期几

weekname = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saterday", "Sunday"]
normal_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
special_month = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]


def judge_year(year: int) -> int:
    if year % 400 == 0:
        return 366
    if year % 100 == 0:
        return 365
    if year % 4 == 0:
        return 366
    else:
        return 365

    
def judge_month_day(days: int, month_list: list) -> str:
    for i in range(len(month_list)):
        if days > month_list[i]:
            days -= month_list[i]
        else:
            return "{}/{}".format(i+1, days)


def func():
    # please define the python3 input here. 
    # For example: a,b = map(int, input().strip().split())
    n = int(input().strip())
    # please finish the function body here.
    days = n + 1
    cur_month_day = ""
    cur_year = 2000
    while True:
        year_days = judge_year(cur_year)
        if days <= year_days:
            if year_days == 365:
                cur_month_day = judge_month_day(days, normal_month)
            else:
                cur_month_day = judge_month_day(days, special_month)
            break
        cur_year += 1
        days -= year_days
    weekday = weekname[(n + 5) % 7]
    # please define the python3 output here. For example: print().
    print("{}/{} {}".format(cur_year, cur_month_day, weekday))

    
if __name__ == "__main__":
    func()