随笔分类 -  C#

摘要:public double Distance(double Longitude1, double latitude1, double Longitude2, double latitude2) { try { double R; double dx, dy, dew; R = 6378137; //地球半径 Longitude1 *= Math.PI / 180.0; latitude1 *= Math.PI / 180.0; Longitude2 *= Math.PI / 180.0; latitude2 *= Math.PI / 180.0; //经度差 dew = Longitude1 阅读全文

posted @ 2012-08-04 15:13 jackning 阅读(662) 评论(0) 推荐(0)

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