poj 2109 pow函数也能这么用?p的开n次方
#include<stdio.h>
#include<cmath>
int main()
{
double n,p;
while(scanf("%lf%lf",&n,&p)!=EOF)
{
printf("%.0f\n",pow(p,1/n));
}
return 0;
}
#include<stdio.h>
#include<cmath>
int main()
{
double n,p;
while(scanf("%lf%lf",&n,&p)!=EOF)
{
printf("%.0f\n",pow(p,1/n));
}
return 0;
}