leetcode-836-easy

Rectangle Overlap

An axis-aligned rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) is the coordinate of its bottom-left corner, and (x2, y2) is the coordinate of its top-right corner. Its top and bottom edges are parallel to the X-axis, and its left and right edges are parallel to the Y-axis.

Two rectangles overlap if the area of their intersection is positive. To be clear, two rectangles that only touch at the corner or edges do not overlap.

Given two axis-aligned rectangles rec1 and rec2, return true if they overlap, otherwise return false.

Example 1:

Input: rec1 = [0,0,2,2], rec2 = [1,1,3,3]
Output: true
Example 2:

Input: rec1 = [0,0,1,1], rec2 = [1,0,2,1]
Output: false
Example 3:

Input: rec1 = [0,0,1,1], rec2 = [2,2,3,3]
Output: false
Constraints:

rec1.length == 4
rec2.length == 4
-109 <= rec1[i], rec2[i] <= 109
rec1 and rec2 represent a valid rectangle with a non-zero area.

思路一：判断 x 是否在重叠区间内

    public boolean isRectangleOverlap(int[] rec1, int[] rec2) {
        return !(rec1[2] <= rec2[0] || rec1[3] <= rec2[1] || rec1[0] >= rec2[2] || rec1[1] >= rec2[3]);
    }