leetcode-674-easy

LongestContinuous Increasing Subsequence

Given an unsorted array of integers nums, return the length of the longest continuous increasing subsequence (i.e. subarray). The subsequence must be strictly increasing.

A continuous increasing subsequence is defined by two indices l and r (l < r) such that it is [nums[l], nums[l + 1], ..., nums[r - 1], nums[r]] and for each l <= i < r, nums[i] < nums[i + 1].

Example 1:

Input: nums = [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5] with length 3.
Even though [1,3,5,7] is an increasing subsequence, it is not continuous as elements 5 and 7 are separated by element
4.
Example 2:

Input: nums = [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2] with length 1. Note that it must be strictly
increasing.
Constraints:

1 <= nums.length <= 104
-109 <= nums[i] <= 109

思路一：向前遍历数组，遍历的时候统计递增子序列的最大长度

    public int findLengthOfLCIS(int[] nums) {
        int max = 1;
        int count = 1;
        for (int i = 0; i < nums.length - 1; i++) {
            if (nums[i + 1] > nums[i]) {
                count++;
            } else {
                max = Math.max(count, max);
                count = 1;
            }
        }
        max = Math.max(count, max);

        return max;
    }