leetcode-551-easy

Student Attendance Record I

You are given a string s representing an attendance record for a student where each character 
signifies whether the student was absent, late, or present on that day. The record only contains the following three characters:

'A': Absent.
'L': Late.
'P': Present.
The student is eligible for an attendance award if they meet both of the following criteria:

The student was absent ('A') for strictly fewer than 2 days total.
The student was never late ('L') for 3 or more consecutive days.
Return true if the student is eligible for an attendance award, or false otherwise.

Example 1:

Input: s = "PPALLP"
Output: true
Explanation: The student has fewer than 2 absences and was never late 3 or more consecutive days.
Example 2:

Input: s = "PPALLL"
Output: false
Explanation: The student was late 3 consecutive days in the last 3 days, so is not eligible for the award.
Constraints:

1 <= s.length <= 1000
s[i] is either 'A', 'L', or 'P'.

思路一：统计字符，注意迟到是需要连续计算的

    public boolean checkRecord(String s) {
        int lateCount = 0;
        int absentCount = 0;

        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == 'A') {
                absentCount++;

            }
        }

        int count = 0;
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == 'L') {
                count++;
            } else {
                lateCount = Math.max(lateCount, count);
                count = 0;
            }
        }
        lateCount = Math.max(lateCount, count);

        return lateCount < 3 && absentCount < 2;
    }