leetcode-492-easy

Construct the Rectangle

A web developer needs to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

The area of the rectangular web page you designed must equal to the given target area.
The width W should not be larger than the length L, which means L >= W.
The difference between length L and width W should be as small as possible.
Return an array [L, W] where L and W are the length and width of the web page you designed in sequence.

Example 1:

Input: area = 4
Output: [2,2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
Example 2:

Input: area = 37
Output: [37,1]
Example 3:

Input: area = 122122
Output: [427,286]
Constraints:

1 <= area <= 107

思路一：遍历 [1, sqrt(n)], 检测是否整除，如果是则符合答案

    public int[] constructRectangle(int area) {
        int[] result = new int[]{area, 1};

        for (int i = 2; i <= Math.sqrt(area); i++) {
            if (area % i == 0) {
                result[0] = area / i;
                result[1] = i;
            }
        }

        return result;
    }