输出日期下一天

#include <iostream>
#include <stdio.h>
#include <sstream>

using namespace std;

int main(int argc, char **argv)
{
    int ret(0);

    string line;
    while (getline(cin, line))
    {
        int year(0), month(0), day(0), hour(0), minute(0), second(0);
        ret = sscanf(line.c_str(), "%4d-%2d-%2d %2d:%2d:%2d", &year, &month, &day, &hour, &minute, &second);
        if (6 != ret)
        {
            cout << "input date format invalid, please input like 2015-12-31 10:30:00" << endl;
            continue;
        }

        struct tm curTm;
        curTm.tm_year = year - 1900;
        curTm.tm_mon = month -1;
        curTm.tm_mday = day;
        curTm.tm_hour = hour;
        curTm.tm_min = minute;
        curTm.tm_sec = second;

        time_t curDaySec = mktime(&curTm);
        time_t lastDaySec = curDaySec + (24 * 60 * 60);

        struct tm * lastTm;
        lastTm = localtime(&lastDaySec);

        char result[100];
        strftime(result, sizeof(result), "%F %T", lastTm);
        cout << "result: " << result << endl;
    }

    return 0;
}