LeetCode - Flatten Binary Tree to Linked List
Given a binary tree, flatten it to a linked list in-place. For example, given the following tree: 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public void flatten(TreeNode root) { Stack<TreeNode> stack = new Stack<>(); helper(root, stack); } public void helper(TreeNode node, Stack<TreeNode> stack) { if (node == null) { return; } if (node.right != null){ stack.push(node.right); } if (node.left != null){ node.right = node.left; node.left = null; } else if(!stack.isEmpty()){ node.right = stack.pop(); } helper(node.right, stack); } }
posted on 2020-04-24 13:42 IncredibleThings 阅读(86) 评论(0) 收藏 举报
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