更加特定密码表解码base64

import base64
dict={0: 'J', 1: 'K', 2: 'L', 3: 'M', 4: 'N', 5: 'O', 6: 'x', 7: 'y', 8: 'U', 9: 'V', 10: 'z', 11: 'A', 12: 'B', 13: 'C', 14: 'D', 15: 'E', 16: 'F', 17: 'G', 18: 'H', 19: '7', 20: '8', 21: '9', 22: 'P', 23: 'Q', 24: 'I', 25: 'a', 26: 'b', 27: 'c', 28: 'd', 29: 'e', 30: 'f', 31: 'g', 32: 'h', 33: 'i', 34: 'j', 35: 'k', 36: 'l', 37: 'm', 38: 'W', 39: 'X', 40: 'Y', 41: 'Z', 42: '0', 43: '1', 44: '2', 45: '3', 46: '4', 47: '5', 48: '6', 49: 'R', 50: 'S', 51: 'T', 52: 'n', 53: 'o', 54: 'p', 55: 'q', 56: 'r', 57: 's', 58: 't', 59: 'u', 60: 'v', 61: 'w', 62: '+', 63: '/', 64: '='}

c='FlZNfnF6Qol6e9w17WwQQoGYBQCgIkGTa9w3IQKw'
base='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/'
flag=""
# print(len(base))
for i in c:
    if i in dict.values():

        key=list(dict.keys())[list(dict.values()).index(i)]#根据值取键号
        # print(key)
        flag+=base[key]#使用键号去base表里找到相应编码,并组合
print(flag)
flag=base64.b64decode(flag)
print(flag)

  

posted @ 2025-07-14 13:13  白嫖帝  阅读(8)  评论(0)    收藏  举报