python 字典get方法
t1 = [['aa'],['ff'],['er']]t2 = [['aa', 11,],['er', 99,]]d2 = dict(t2)res = [[k[0], d2.get(k[0], 0)] for k in t1]
t1 = [['aa'],['ff'],['er']]t2 = [['aa', 11,],['er', 99,]]d2 = dict(t2)res = [[k[0], d2.get(k[0], 0)] for k in t1]