随笔分类 - SQL
摘要:https://www.cnblogs.com/shoshana-kong/p/16580840.html with name1 as ( select 脚本1 ), name2 as ( select 脚本2 ) select * from name1 a innert join name2 b
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摘要:DELETE t1 FROM tmp202306253 t1INNER JOIN ( SELECT sid, buy_date, MAX(pkId) AS max_value FROM tmp202306253 GROUP BY sid, buy_date HAVING COUNT(*) > 1)
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