带有头节点的单链表

#include<stdio.h>
#include<stdlib.h>
#define N 3//不包括头节点共N个
//创建结构体
typedef struct Node {
	int value;
	struct Node* next;
}Node,*pNode;
int main() {
	pNode head, left, right;
	head =left=(pNode)malloc(sizeof(Node));//head,left指向同一个内存空间,如何没有头节点，整个链表缺少把柄，无法找到之前创建的链表，也无法遍历
	head->value = N;
	//创建链表
	for (int i = 0; i < N; i++) {
		right = (pNode)malloc(sizeof(Node));
		printf("Input:The value of Node %d:", i + 1);
		scanf("%d", &right->value);
		left->next = right;
		left = right;

	}
	right->next = NULL;
	//遍历链表
	int count = 1;
	for (int i = 0; i < 21; i++)
		printf("*");
	pNode p = head;
	printf("\nThe amount of Nodes:%d\n", p->value);
	p = p->next;

	while (p != NULL) {
	
		printf("Output:The value of Node %d:%d\n", count,p->value);
		count++;
		p = p->next;
	}
	


	return 0;
}

 调试：