CDOJ--1846

原题链接：http://acm.uestc.edu.cn/problem.php?pid=1846

分析：设置front记录前一个单词即可，容易题。

Angry Grammar Nazi

 1 #include<stdio.h>
 2 #include<string.h>
 3 int lol(char string[105])
 4 {
 5     int i,len;
 6     len=strlen(string);
 7     for(i=0;i<len-2;i++)
 8     {
 9         if(string[i]=='l'&&string[i+1]=='o'&&string[i+2]=='l')return 1;
10     }
11     return 0;
12 }
13 int main()
14 {
15    int T,i,j,ans,flag,count;
16    char str[105],front[105];
17    scanf("%d",&T);
18    getchar();
19    while(T--)
20    {
21        memset(str,0,sizeof(str));
22        ans=0;flag=0;
23        gets(str);
24        j=0;
25        memset(front,0,sizeof(front));
26        count=0;
27        for(i=0;;i++)
28        {
29            if(str[i]>='a'&&str[i]<='z')
30            front[j++]=str[i];
31            else
32            {
33                count++;
34                front[j]='\0';
35                if(j==1&&front[0]=='u')ans++;
36                else if(j==2&&strcmp(front,"ur")==0)ans++;
37                else if(strcmp(front,"should")==0||strcmp(front,"would")==0){flag=1;count=0;}
38                else if(strcmp(front,"of")==0&&flag==1&&count==1)ans++;
39                else if(lol(front)==1)ans++;
40                j=0;
41                memset(front,0,sizeof(front));
42            }
43            if(str[i]=='\0')break;
44        }
45        printf("%d\n",ans*10);
46    }
47    return 0;
48 }
49 
50

 

 

posted @ 2013-05-31 20:27  EtheGreat  阅读(170)  评论(0)    收藏  举报