实验1

任务1

运行代码
#include <stdio.h>
int main()
{
	printf(" 0 \n");
	printf("<H>\n");
	printf("I I\n");
	
	return 0;
	
	
}
运行截图

![截图](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016145146817-1998297115.png)
改变后的代码
#include <stdio.h>
int main()
{
	printf(" 0 \n");
	printf("<H>\n");
	printf("I I\n");
	printf(" 0 \n");
	printf("<H>\n");
	printf("I I\n");
	
	return 0;
}
运行截图

![截图2](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016145637006-1494636303.png)
第二次改变后的代码
#include <stdio.h>
int main()
{
	printf(" 0\t 0 \n");
	printf("<H>\t <H>\n");
	printf("I I\t I I\n");
	
	return 0;
}
运行截图

![截图2](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016150326808-1845681296.png)

任务2

运行代码
#include <stdio.h>
int main()
{
	double a, b, c;
	
	scanf("%lf%lf%lf", &a, &b, &c);
	
	if(a+b>c && b+c>a && a+c>b)
	    printf("能构成三角形\n");
	else
	    printf("不能构成三角形\n");
	
	return 0; 
	
}

运行截图

![屏幕截图 2026-10-16 163711](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016164006274-2049727333.png)

任务3

#include <stdio.h>
int main()
{
	char ans1, ans2;
	
	printf("每次课及时预习/复习了没?(是-输入y或Y, 否-输入n或N): ");
	ans1 = getchar();
	
	getchar();
	
	printf("\n动手敲代码实现了没?(是-输入y或Y, 否-输入n或N): ");
	ans2 = getchar();
	
	if(ans1 == 'y' || ans2 == 'y' && ans1 == 'Y' || ans2 == 'Y' )
	printf("\n罗马不是一天建成的,继续保持哦:)\n");
	else
	printf("\n罗马不是一天毁灭的,我们来建设吧\n");
	
	return 0;
}
运行截图

![屏幕截图 2026-10-16 165643](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016165805077-1796407180.png)

![屏幕截图 2026-10-16 165929](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016165959578-1289731455.png)

任务4

运行代码
#include <stdio.h>
#include <math.h>
int main()
{
	int year;
	
	double sec = 1000000000;
	double year_d = sec / (365 * 24 * 60 * 60);
	year = round(year_d);
	
	printf("10亿秒约等于%d年\n", year);
	return 0;
	
}
运行截图

![屏幕截图 2026-10-16 170759](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016170845488-932138094.png)

任务5

运行代码
#include <stdio.h>
int main()
{
	double c, f;
	
	scanf("%lf", &c);
	f=9.0/5.0*c + 32;
	
	printf("摄氏度c = %.2f时,华氏温度f = %.2f\n\n", c, f);
	
	return 0;
}
运行截图

![屏幕截图 2026-10-16 171657](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016171808786-904227128.png)

任务6

运行代码
#include <stdio.h>
#include <math.h>
int main()
{
	double a, b, c;
	double s, area;
	
	scanf("%lf%lf%lf", &a, &b, &c);
	s = (a + b + c)/2.0;
	area = sqrt(s * (s-a) * (s-b) * (s-c));
	printf("a = %.0f, b = %.0f, c = %.0f, area = %.3f\n", a, b, c, area);
	
	return 0;
	
}
运行截图

![屏幕截图 2026-10-16 182512](https://img2024.cnblogs.com/blog/3861597/202610/3861597-20261016182608239-1848952229.png)


	
posted @ 2026-10-16 18:29  郝昱哲  阅读(6)  评论(0)    收藏  举报