实验2

实验二

task1代码:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include<stdlib.h>

#define N 5

int main() {
    int number;
    int i;

    srand(time(0));     // 以当前系统时间作为随机种子
    for(i = 0; i < N; ++i) {
        number = rand() % 100 + 1;
        printf("20490042%04d\n", number);
    }

	system("pause");

    return 0;
}

运行结果:
image

问题1:生成1-100随机数
问题2:输出4个数不足补零
问题3:生成12位数字

task2代码:

#include <stdio.h>

int main() {
    int choice, quantity;
    float total_price = 0, amount_paid, change;

    while (1) {
        printf("\n自动饮料售卖机菜单:\n");
        printf("1. 可乐 - 3 元/瓶\n");
        printf("2. 雪碧 - 3 元/瓶\n");
        printf("3. 橙汁 - 5 元/瓶\n");
        printf("4. 矿泉水 - 2 元/瓶\n");
        printf("0. 退出购买流程\n");
        printf("请输入饮料编号: ");
        scanf("%d", &choice);

        if (choice == 0)
            break;

        if (choice < 1 || choice > 4) {
            printf("无效的饮料编号,请重新输入。\n");
            continue;
        }

        printf("请输入购买的数量: ");
        scanf("%d", &quantity);

        if (quantity < 0) {
            printf("购买数量不能为负数,请重新输入。\n");
            continue;
        }

        switch (choice) {
            case 1:
            case 2:
                total_price += 3 * quantity;
                break;
            case 3:
                total_price += 5 * quantity;
                break;
            case 4:
                total_price += 2 * quantity;
                break;
        }

        printf("请投入金额: ");
        scanf("%f", &amount_paid);

        change = amount_paid - total_price;
        printf("本次购买总价: %.2f 元\n", total_price);
        printf("找零: %.2f 元\n", change);

        total_price = 0;
    }

    printf("感谢您的购买,欢迎下次光临!\n");
    return 0;
}

运行结果:
image

问题1:清空总价格防止二次计算时初值不为0
问题2:break直接停止,continue停止本次后继续
问题3:没必要,choice的值只有01234

task3代码:

#include<stdio.h>

int main()
{
	char color;

	printf("请输入信号灯颜色,r代表red,g代表green,y代表yellow:");

	while(scanf("%c",&color) != EOF){
		if(color == 'r'){
			printf("stop\n");
		}else if(color == 'g'){
			printf("go go go\n");
		}else if(color == 'y'){
			printf("wait a minute\n");
		}else{
			printf("something must be wrong\n");
		}
		printf("请输入信号灯颜色,r代表red,g代表green,y代表yellow:");
		getchar();
	}

	return 0;
}

运行结果:
image

task4代码:

#include<stdio.h>
#include<stdlib.h>

int main()
{
	double x,max,min,sum;
	sum=0;
	max=0;

	printf("输入今日开销,到-1停止\n");
	scanf("%lf",&x);
	min = x;

	while(x != -1){
		sum += x;

		if(x>max){
			max = x;
		}

		if(x<min){
			min = x;
		}
		scanf("%lf",&x);
	}

	printf("今日累计消费总额:%.1lf\n今日最高一笔开销:%.1lf\n今日最低一笔开销:%.1lf\n",sum,max,min);

	system("pause");

	return 0;
}

运行结果:
image

task5代码:

#include<stdio.h>
#include <stdlib.h>
#include <time.h>


#define N 3
int main()
{
	int day,i,guess;

	printf("猜猜2025年4月哪一天是你的lucky day\n");

	srand(time(0));
	day = rand() % 30 + 1;

	
	for (i = 0; i < N; i++)
	{
		if (i == 0)
			printf("开始喽,你有三次机会,猜吧(1~30):");
		else
			printf("再猜(1~30):");
		scanf("%d", &guess);
		

		if (guess > day)
			printf("你猜的日期晚了,你的lucky day在前面哦\n");
		else if (guess < day)
			printf("你猜的日期早了,你的lucky day还没到呢\n");
		else
		{
			printf("哇,猜中了:-)\n");
			break;
		}
	}
		


	if (i == 3)
		printf("次数用完啦。悄悄告诉你,4月你的lucky day是%d号\n", day);

	system("pause");

	return 0;
}

运行结果:
image

image

task6代码:

#include<stdio.h>
#include<stdlib.h>

int main()
{

	int n,i,j;
	printf("input n: ");
	scanf("%d", &n);

	for (i = n; i >0; i--)
	{
		for (j = 0; j < n-i; j++)
			printf(" \t");

		for (j = 0; j < 2*i-1; j++)
			printf(" O \t");

		for (j = 0; j < n - i; j++)
			printf(" \t");

		printf("\n");

		for (j = 0; j < n - i; j++)
			printf(" \t");

		for (j = 0; j < 2*i-1; j++)
			printf("<H>\t");

		for (j = 0; j < n - i; j++)
			printf(" \t");

		printf("\n");

		for (j = 0; j < n - i; j++)
			printf(" \t");

		for (j = 0; j < 2*i-1; j++)
			printf("I I\t");

		for (j = 0; j < n - i; j++)
			printf(" \t");

		printf("\n");
		printf("\n");
	}

	system("pause");

	return 0;
}

运行结果:
image

image

posted @ 2025-03-18 17:25  hya2044  阅读(7)  评论(0)    收藏  举报