简单的字典排序,根据value值得大小排序:
def sort_dict(dict_words):
"""
字典排序
:param dict_words:
:return:
"""
keys = dict_words.keys()
values = dict_words.values()
list_one = [(key, val) for key, val in zip(keys, values)]
list_sort = sorted(list_one, key=lambda x: x[1], reverse=True)
return list_sort