二分查找及各种变体实现

public class BinarySearch {

    // 二分查找
    public static int bSearch(int[] nums, int target) {
        int n = nums.length;
        int low = 0;
        int high = n - 1;

        while (low <= high) {
            int mid = low + ((high - low) >> 1);
            if (nums[mid] > target) {
                high = mid - 1;
            } else if (nums[mid] < target) {
                low = mid + 1;
            } else {
                return mid;
            }
        }

        return -1;
    }

    // 查找第一个值等于给定值的元素
    public static int searchFirstTarget(int[] nums, int target) {
        int n = nums.length;
        int low = 0;
        int high = n - 1;

        while (low <= high) {
            int mid = low + ((high - low) >> 1);
            if (nums[mid] > target) {
                high = mid - 1;
            } else if (nums[mid] < target) {
                low = mid + 1;
            } else {
                if (mid == 0 || nums[mid - 1] != target) {
                    return mid;
                } else {
                    high = mid - 1;
                }
            }
        }

        return -1;
    }

    // 查找最后一个值等于给定值的元素
    public static int searchLastTarget(int[] nums, int target) {
        int n = nums.length;
        int low = 0;
        int high = n - 1;

        while (low <= high) {
            int mid = low + ((high - low) >> 1);
            if (nums[mid] > target) {
                high = mid - 1;
            } else if (nums[mid] < target) {
                low = mid + 1;
            } else {
                if (mid == n - 1 || nums[mid + 1] != target) {
                    return mid;
                } else {
                    low = mid + 1;
                }
            }
        }

        return -1;
    }

    // 查找第一个大于等于给定值的元素
    public static int searchFirstGreaterOrEqual2Target(int[] nums, int target) {
        int n = nums.length;
        int low = 0;
        int high = n - 1;

        while (low <= high) {
            int mid = low + ((high - low) >> 1);
            if (nums[mid] >= target) {
                if (mid == 0 || nums[mid - 1] < target) {
                    return mid;
                } else {
                    high = mid - 1;
                }
            } else {
                low = mid + 1;
            }
        }

        return -1;
    }

    // 查找第一个小于等于给定值的元素
    public static int searchLastLessOrEqual2Target(int[] nums, int target) {
        int n = nums.length;
        int low = 0;
        int high = n - 1;

        while (low <= high) {
            int mid = low + ((high - low) >> 1);
            if (nums[mid] <= target) {
                if (mid == n - 1 || nums[mid + 1] > target) {
                    return mid;
                } else {
                    low = mid + 1;
                }
            } else {
                high = mid - 1;
            }
        }

        return -1;
    }

    // 查找元素的第一个和最后一个位置
    public static int[] searchRange(int[] nums, int target) {
        int n = nums.length;
        int low = 0;
        int high = n - 1;

        int[] ans = new int[]{-1, -1};

        while (low <= high) {
            int mid = low + ((high - low) >> 1);
            if (nums[mid] < target) {
                low = mid + 1;
            } else if (nums[mid] > target) {
                high = mid - 1;
            } else {
                int start = mid;
                int end = mid;
                while (start >= 0 && nums[start] == target) {
                    start--;
                }
                while (end <= n - 1 && nums[end] == target) {
                    end++;
                }
                ans[0] = start + 1;
                ans[1] = end - 1;
                return ans;
            }
        }

        return ans;
    }
}
posted @ 2021-11-18 00:33  hunter-w  阅读(28)  评论(0编辑  收藏  举报