jquery ajax promise
$request = $.getJSON('test.php');
    $request.done(process1);
    $request.done(process2);
    $request.always(process3);
    function process1() {
        console.log('process1:');
    }
    function process2() {
        console.log('process2');
    }
    function process3() {
        console.log('process3');
    }
$promise = $.Deffered()
 
                
            
         
         浙公网安备 33010602011771号
浙公网安备 33010602011771号