每日小题6

把a和b合并成c的样子
c = ['a,1,2','b,3,22,1','c,3,4','d,2']
dic={}
a = ['a,1','b,3,22','c,3,4',]
b = ['a,2','b,1','d,2',]
c=[]
for i in a:
    try:
        dic[i[0]]=dic[i[0]]+str(i[1::])
    except:
        dic[i[0]]=''
        dic[i[0]] = dic[i[0]] + str(i[1::])
for i in b:
    try:
        dic[i[0]] = dic[i[0]] + str(i[1::])
    except:
        dic[i[0]] = ''
        dic[i[0]] = dic[i[0]] + str(i[1::])

for a,i in dic.items():
    c.append(a+i)
print(c)


1.7.2 有一个多层嵌套列表A = [1,2,[3,4,[34,32,[2,3,5,6,......]]]] 
请写一段代码遍历A中的每个元素并打印出来。
A = [1,2,[3,4,[34,32,[2,3,5,6]]]]
def cc(o):
    for i in o:
        if type(i) == list:
             cc(i)
        else:
            print(i)
cc(A)
lst = [1,2,4,6,8,16,32,64,128,256,512,1024,32769,65536,4294967296,]
{
1:[1,2,4,6,8],
2:  [16,32,64,],
3:  [128,256,512,],
4:  [1024,],
5:  [32769,65536,],
10:  [4294967296],
}


一个数组[3,4,1,2,5,6,6,5,4,3,3]写一个函数找出数组中没有重复的数的总和
dic={}
count=0
a=[3,4,1,2,5,6,6,5,4,3,3]
for i in a:
    dic[i]=dic.setdefault(i,0)+1
for a,b in dic.items():
    if b==1:
        count+=a
print(count)


arr=[1,2,3]
def bar():
    # global arr
    arr+=[5]
bar()
print(arr)
没有global找不到arr报错


def say_hi(func):
    def wrapper(*args,**kwargs):
        print("HI")
        ret=func(*args,**kwargs)
        print("BYE")
        return ret
    return wrapper
    # def say_yo(func):下面的不执行
@say_hi
def func():
    print("ROCK&ROLL")
func()