KMP
//时间复杂度O(n)
#include <iostream>
using namespace std;
const int N = 100010, M = 1000010;
int n, m;
char p[N], s[M];
int ne[N];
int main() {
cin >> n >> p + 1 >> m >> s + 1;
//求next数组
for(int i = 2, j = 0; i <= n; i ++ ) {
while(j && p[i] != p[j + 1]) j = ne[j];
if(p[i] == p[j + 1]) j ++ ;
ne[i] = j;
}
//匹配过程
for(int i = 1, j = 0; i <= m; i ++ ) {
while(j && s[i] != p[j + 1]) j = ne[j];
if(s[i] == p[j + 1]) j ++ ;
if(j == n) {
//匹配成功
printf("%d ", i - n);
j = ne[j];
}
}
return 0;
}
拓展题