实验7

第一题

include <stdio.h>

define N 80

define M 100

typedef struct {
char name[N]; // 书名
char author[N]; // 作者
} Book;
void write();
void read();
int main() {
printf("测试1: 把图书信息写入文本文件\n");
write();
printf("\n测试2: 从文本文件读取图书信息, 打印输出到屏幕\n");
read();
return 0;
}
void write() {
Book x[] = { {"《雕塑家》", "斯科特.麦克劳德"},
{"《灯塔》", "克里斯多夫.夏布特"},
{"《人的局限性》", "塞缪尔.约翰生"},
{"《永不停步：玛格丽特.阿特伍德传》", "罗斯玛丽.沙利文"},
{"《大地之上》", "罗欣顿·米斯特里"},
{"《上学记》", "何兆武"},
{"《命运》", "蔡崇达"} };
int n, i;
FILE *fp;
// 计算数组x中元素个数
n = sizeof(x) / sizeof(x[0]);
// 以写的方式打开文本文件data1.txt
fp = fopen("data1.txt", "w");
// 如果打开文件失败，输出提示信息并返回
if(fp == NULL) {
printf("fail to open file to write\n");
return;
}
// 将结构体数组x中的图书信息格式化写到fp指向的文件data1.txt
for(i = 0; i < n; ++i)
fprintf(fp, "%-40s %-20s\n", x[i].name, x[i].author);
fclose(fp);
}
void read() {
Book x[M];
int i, n;
int number;
FILE *fp;
// 以读的方式打开文本文件data1.txt
fp = fopen("data1.txt", "r");
// 如果打开文件失败，输出提示信息并返回
if(fp == NULL) {
printf("fail to open file to read\n");
return;
}
// 从文件中读取图书信息，保存到结构体数组x中
i = 0;
while(!feof(fp)) {
number = fscanf(fp, "%s%s", x[i].name, x[i].author);
if(number != 2)
break;
i++;
}
n = i;
// 将图书信息打印输出到屏幕上
for(i = 0; i < n; ++i)
printf("%d. %-40s%-20s\n", i+1, x[i].name, x[i].author);
fclose(fp);
}

第二题

include <stdio.h>

define N 80

define M 100

typedef struct {
char name[N]; // 书名
char author[N]; // 作者
} Book;
void write();
void read();
int main() {
printf("测试1: 把图书信息以数据块方式写入二进制文件\n");
write();
printf("\n测试2: 从二进制文件读取图书信息, 打印输出到屏幕\n");
read();
return 0;
}
void write() {
Book x[] = { {"《雕塑家》", "斯科特.麦克劳德"},
{"《灯塔》", "克里斯多夫.夏布特"},
{"《人的局限性》", "塞缪尔.约翰生"},
{"《永不停步：玛格丽特.阿特伍德传》", "罗斯玛丽.沙利文"},
{"《大地之上》", "罗欣顿·米斯特里"},
{"《上学记》", "何兆武"},
{"《命运》", "蔡崇达"} };
int n;
FILE *fp;
// 计算数组x中元素个数
n = sizeof(x) / sizeof(x[0]);
// 以写的方式打开二进制文件data2.dat
fp = fopen("data2.dat", "wb");
// 如果打开文件失败，输出提示信息并返回
if(fp == NULL) {
printf("fail to open file to write\n");
return;
}
// 将结构体数组x中的图书信息以数据块方式写入二进制文件data2.dat
fwrite(x, sizeof(Book), n, fp);
fclose(fp);
}
void read() {
Book x[M];
int i, n;
int number;
FILE *fp;
// 以读的方式打开二进制文件data2.dat
fp = fopen("data2.dat", "rb");
// 如果打开文件失败，输出提示信息并返回
if(fp == NULL) {
printf("fail to open file to read\n");
return;
}
// 从二进制文件data2.dat以数据块方式读取图书信息存储到结构体数组x
i = 0;
while(!feof(fp)) {
number = fread(&x[i], sizeof(Book), 1, fp);
if(number != 1)
break;
i++;
}
// 在屏幕上打印输出
n = i;
for(i = 0; i < n; ++i)
printf("%d. %-40s%-20s\n", i+1, x[i].name, x[i].author);
fclose(fp);
}
第三题

include <stdio.h>

define N 5

define M 80

void write();
void read_str();
void read_char();
int main() {
printf("测试1: 把一组字符信息以字符串方式写入文本文件\n");
write();
printf("\n测试2: 从文件以字符串方式读取, 输出到屏幕\n");
read_str();
printf("\n测试3: 从文件以单个字符方式读取, 输出到屏幕\n");
read_char();
return 0;
}
void write() {
char *ptr[N] = { "Working's Blues",
"Everything Will Flow",
"Streets of London",
"Perfect Day",
"Philadelphia"};
int i;
FILE *fp;
fp = fopen("data3.txt", "w");
if(!fp) {
printf("fail to open file to write\n");
return;
}
for(i = 0; i < N; ++i) {
fputs(ptr[i], fp);
fputs("\n", fp);
}
fclose(fp);
}
void read_str() {
char songs[N][M];
int i;
FILE *fp;
fp = fopen("data3.txt", "r");
if(!fp) {
printf("fail to open file to read\n");
return;
}
for(i = 0; i < N; ++i)
fgets(songs[i], 80, fp);
for(i = 0; i < N; ++i)
printf("%d. %s", i+1, songs[i]);
fclose(fp);
}
void read_char() {
char ch;
FILE *fp;
fp = fopen("data3.txt", "r");
if(!fp) {
printf("fail to open file to read\n");
return;
}
while(!feof(fp)) {
ch = fgetc(fp);
if(ch == EOF)
break;
putchar(ch);
}
fclose(fp);
}
第四题

include <stdio.h>

define N 10

define M 30

int count_line();
int count_words();
int main()
{
printf("data4.txt统计结果：\n");
printf("行数：%d\n", count_line());
printf("字符数（不计空白符）：%d\n", count_words());
return 0;
}
int count_line()
{
int acount = 0;
char line[M];
FILE *fp;
fp = fopen("E:\学科资料（整理）\大一下\C语言实验\实验7数据文件及部分代码\实验7数据文件及部分代码\data4.txt", "r");
if (!fp)
{
printf("fail to open file to read\n");
return -1;
}
while (fgets(line, M, fp) != NULL)
{
acount++;
}
fclose(fp);
return acount;
}
int count_words()
{
int char_count = 0;
char line[M];
FILE *fp;
fp = fopen("E:\学科资料（整理）\大一下\C语言实验\实验7数据文件及部分代码\实验7数据文件及部分代码\data4.txt", "r");
if (!fp)
{

 printf("fail to open file to read\n");
 return -1;
}
while (fgets(line, M, fp) != NULL)
{
    for (int i = 0; line[i] != '\0'; i++)
    {
        
        if (line[i] != ' ' && line[i] != '\t' && line[i] != '\n' && line[i] != '\r')
        {
            char_count++;
        }
    }
}
fclose(fp);
return char_count;

}
第五题

include <stdio.h>

include <string.h>

define N 10

typedef struct {
long id;
char name[20];
float objective;
float subjective;
float sum;
char result[10];
} STU;

// 函数声明
void read(STU st[], int n);
void write(STU st[], int n);
void output(STU st[], int n);
int process(STU st[], int n, STU st_pass[]);

int main() {
STU stu[N], stu_pass[N];
int cnt;
double pass_rate;

printf("从文件读入%d个考生信息...\n", N);
read(stu, N);

printf("\n对考生成绩进行统计...\n");
cnt = process(stu, N, stu_pass);

printf("\n通过考试的名单:\n");
output(stu, N);  
write(stu, N);    

pass_rate = 1.0 * cnt / N;
printf("\n本次等级考试通过率: %.2f%%\n", pass_rate*100);

return 0;

}

void output(STU st[], int n) {
int i;

printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t结果\n");
for (i = 0; i < n; i++)
    printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", st[i].id, st[i].name, st[i].objective, st[i].subjective, st[i].sum, st[i].result);

}
void read(STU st[], int n) {
int i;
FILE *fin;
fin = fopen("E:\学科资料（整理）\大一下\C语言实验\实验7数据文件及部分代码\实验7数据文件及部分代码\examinee.txt", "r");
if (!fin) {
printf("fail to open file\n");
return;
}
while (!feof(fin)) {
for (i = 0; i < n; i++)
fscanf(fin, "%ld %s %f %f", &st[i].id, st[i].name, &st[i].objective, &st[i].subjective);
}
fclose(fin);
}
void write(STU s[], int n) {

int i;
FILE *fp;
fp = fopen("E:\\学科资料（整理）\\大一下\\C语言实验\\程序练习\\strawpaper\\strawpaper\\list_pass.txt","w");

if(fp==NULL)
{
    printf("fail to open file to write\n");
    return;
}
for(i=0;i<n;++i)
{
    if(s[i].sum>=60)
    {
        fprintf(fp,"%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].result);
    }
}
fclose(fp);

}
int process(STU st[], int n, STU st_pass[]) {

int i, j=0;

for(i=0;i<n;++i)
{
    st[i].sum = st[i].objective+st[i].subjective;
    if(st[i].sum>=60)
    {
        strcpy(st[i].result, "通过");
        st_pass[j++]=st[i];
    }
    else
        strcpy(st[i].result, "未通过");
}
return j;

}
第六题

include<stdio.h>

include<string.h>

include<time.h>

include<stdlib.h>

define N 5

define M 80

struct student
{
char id[10];
char name[10];
char num_class[30];
}STU；
int main()
{
struct student x[M], y[N];
char name_file[50];
char filePath[200];
int i=0,j=0, k,number;
FILE *fp;
srand(time(NULL));
printf("------------------20250525中奖名单-------------------\n");
fp = fopen("E:\学科资料（整理）\大一下\C语言实验\实验7数据文件及部分代码\实验7数据文件及部分代码\list.txt","r");
if(!fp)
{
printf("fail to open file to read\n");
return 0;
}
while(!feof(fp))
{
number = fscanf(fp, "%s%s%s", x[i].id, x[i].name,x[i].num_class);
if(number != 3)
break;
i++;
}
fclose(fp);
while(j<5)
{
k=rand()%79;
y[j++]=x[k];
printf("%-10s%-10s%-30s\n", x[k].id, x[k].name, x[k].num_class);
}
printf("输入保存文件名：");
scanf("%s",name_file);
sprintf(filePath, "E:\学科资料（整理）\大一下\C语言实验\实验7数据文件及部分代码\实验7数据文件及部分代码\%s.txt", name_file);
fp=fopen(filePath,"w");
if(fp==NULL)
{
printf("fail to open file to write\n");
return 0;
}
for(j=0;j<N;++j)
{
fprintf(fp,"%-10s%-10s%-30s\n",y[j].id, y[j].name,y[j].num_class);
}
fclose(fp);




return 0;

}

posted @ 2025-06-04 19:31  祖国人和劳大  阅读(29)  评论(0)    收藏  举报