MILtracking目标跟踪解析

MILtracking目标跟踪解析

三种概率

在传统的机器学习中,样本只有一个包标签。但是在MIL中,有样本与样本集合的概念,样本集合有包标签\(y_{bag}​\)(若集合含有正样本,包标签为1,否则0),故样本除了具有样本标签\(y_{sample}​\)还有包标签\(y_{bag}​\)。通过Noisy-OR模型可以由集合各元素的样本标签计算该集合的包标签:

\[p\left( y_{bag}=1\left|\right.X_{n}\right)=1-\prod_{n} \left(1-p\left(y_{bag}=1\left|\right. x_{i} \right ) \right ) \]

其中\(X_{n}\)是含有n个样本的集合\(x_{i}\)是集合中的一个元素。

样本包标签后验概率推导

对于任意一个样本\(x\)\(p\left( y_{bag}=1\left|\right.x\right)\),我们可以通过naive bayes导出:

\[\begin{split} p\left( y_{bag}=1\left|\right.x\right) &=\frac{p\left( x\left|\right. y_{bag}=1\right)p\left(y_{bag}=1 \right)}{p\left( x\left|\right. y_{bag}=0\right)p\left(y_{bag}=0 \right)+p\left( x\left|\right. y_{bag}=1\right)p\left(y_{bag}=1 \right)} \\ &=\frac{A}{B+A}=\frac{1}{{\frac{A}{B}}^{-1}+1}=\frac{1}{e^{-\ln\frac{A}{B}}+1}=\sigma\left( \ln\frac{A}{B}\right)\\ &=\sigma \left( \ln\frac{p\left( x\left|\right. y_{bag}=1\right)p\left(y_{bag}=1 \right)}{p\left( x\left|\right. y_{bag}=0\right)p\left(y_{bag}=0 \right)}\right)\\ \\ &又因为p\left(y_{bag}=1 \right)=p\left(y_{bag}=0 \right)\\ \\ &=\sigma \left( \ln\frac{p\left( x\left|\right. y_{bag}=1\right)}{p\left( x\left|\right. y_{bag}=0\right)}\right)\\ \\ &又因为服从naive bayes假设(观测样本维度独立) \\ &=\sigma \left( \ln\frac{\prod p\left( x_{i}\left|\right. y_{bag}=1\right)}{\prod p\left( x_{i}\left|\right. y_{bag}=0\right)}\right)=\sigma \left( \ln \prod \frac{ p\left( x_{i}\left|\right. y_{bag}=1\right)}{ p\left( x_{i}\left|\right. y_{bag}=0\right)}\right)\\ &=\sigma \left( \sum \ln\frac{ p\left( x_{i}\left|\right. y_{bag}=1\right)}{ p\left( x_{i}\left|\right. y_{bag}=0\right)}\right) \end{split} \]

弱分类器与强分类器

设弱分类器

\[h_{i}= \ln\frac{ p\left( x_{i}\left|\right. y_{bag}=1\right)}{ p\left( x_{i}\left|\right. y_{bag}=0\right)} \]

\(h_{1},h_{2},...,h_{n}\)级联构成的强分类器为

\[H_{n}=\sum \ln\frac{ p\left( x_{i}\left|\right. y_{bag}=1\right)}{ p\left( x_{i}\left|\right. y_{bag}=0\right)}=\sum h_{i} \]

在上一次跟踪结果附近某范围采样一个集合\(X_{near}\),远处采样一个集合\(X_{far}\).假设跟踪结果有漂移,但真实位置仍然落在\(X_{near}\),则\(X_{near}\)的包标签为1,\(X_{far}\)的包标签为0,即已知了包标签。进而可求取\(p\left( x_{i}\left|\right. y_{bag}=1\right)\)\(p\left( x_{i}\left|\right. y_{bag}=0\right)\)的分布

\[p\left( x_{i}\left|\right. y_{bag}=1\right) \sim N\left( \mu_{i}^{near},\sigma_{i}^{near}\right), p\left( x_{i}\left|\right. y_{bag}=0\right) \sim N\left( \mu_{i}^{far},\sigma_{i}^{far}\right)\]

posted @ 2017-07-25 18:35  七厘米光影  阅读(2036)  评论(0编辑  收藏  举报