实验3

实验1

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<Windows.h>
#define N 80

void print_text(int line, int col, char test[]);
void print_spaces(int n);
void print_blank_lines(int n);

int main()
{
    int line, col, i;
    char test[N] = "hi,November~";

    srand(time(0));

    for ( i = 1; i <=10; i++)
    {
        line = rand() % 25; 
        col = rand() % 80;
        print_text(line, col, test);
        Sleep(1000);
    }
    return 0;
}
void print_spaces(int n) {
    int i;
    for (i = 1; i <= n; ++i)
        printf(" ");
}
void print_blank_lines(int n) {
    int i;
    for (i = 1; i <= n; ++i)
        printf("\n");
}
void print_text(int line, int col, char text[]) {
    print_blank_lines(line - 1); // 打印(line-1)行空行
    print_spaces(col - 1); // 打印(col-1)列空格
    printf("%s", text); // 在第line行、col列输出text中字符串
}

 实验2

#include <stdio.h>
long long fac(int n); // 函数声明
int main() {
    int i, n;
    printf("Enter n: ");
    scanf_s("%d", &n);
    for (i = 1; i <= n; ++i)
        printf("%d! = %lld\n", i, fac(i));
    return 0;
}
// 函数定义
long long fac(int n) {
    static long long p = 1;
    printf("p=%lld\n", p);
    p = p * n;
    return p;
}

 

#include <stdio.h>
int func(int, int); // 函数声明
int main() {
int k = 4, m = 1, p1, p2;
p1 = func(k, m); // 函数调用
p2 = func(k, m); // 函数调用
printf("%d, %d\n", p1, p2);
return 0;
}
// 函数定义
int func(int a, int b) {
static int m = 0, i = 2;
i += m + 1;
m = i + a + b;
return m;
}

 

实验3

#include <stdio.h>
long long func(int n); // 函数声明
int main() {
    int n;
    long long f;
    while (scanf_s("%d", &n) != EOF) {
        f = func(n); // 函数调用
        printf("n = %d, f = %lld\n", n, f);
    }
    return 0;
}
long long func(int n)
{
    long long i;
    int k = 1;
    if (n==1)
    {
        return 1;
    }
    else
    {
        for ( i = 1; i <n; i++)
        {
        k = k * 2;
        }
     k += func(n-1);
    return k;
    }

 实验4

迭代1：

#include <stdio.h>
int func(int n, int m);
int main() {
    int n, m;
    while (scanf_s("%d%d", &n, &m) != EOF)
        printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
    return 0;
}
int func(int n, int m)
{
    int i,N=1,M=1,k=1,ans;
    for ( i =1; i <=n; i++)
    {
        N *= i;
    }
    for ( i = 1; i <=m; i++)
    {
        M *= i;
    }
    for ( i = 1; i <=(n-m); i++)
    {
        k *= i;
    }
    ans = N / (M * k);
    return ans;
}

 递归2：

#include <stdio.h>
int func(int n, int m);
int main() {
    int n, m;
    while (scanf_s("%d%d", &n, &m) != EOF)
        printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
    return 0;
}
int func(int n, int m)
{
    int k = 0;
    if (m==1)
    {
        return n;
    }
    else if(m==n)
    {
        return 1;
    }
    else
    {
        k = func(n - 1, m) + func(n - 1, m - 1);
    }
}

 实验5

#include<stdio.h>
void move(int x, int y)
{
    printf("%c->%c\n", x, y);
}
int hanoi(int n, char a, char b, char c)
{
    static int k=0;
    k++;
    if (n==1)
    {
        move(a, c);
    }
    else
    {
        hanoi(n - 1, a, c, b);
        move(a, c);
        hanoi(n - 1, b, a, c);
    }
    return k;
}
int main()
{
    int n = 0;
    scanf_s("%d", &n);
    printf("一共移动了%d次", hanoi(n, 'A', 'B', 'C'));
    return 0;
}

 实验6

#include<stdio.h>
#include<math.h>
long func(long s);
int main()
{
    long s, t;
    printf("Enter a number:");
    while (scanf_s("%ld",&s)!=EOF)
    {
        t = func(s);
        printf("new number is:%ld\n\n", t);
        printf("Enter a number:");
    }
    return 0;
}
long func(long s)
{
    long k,j,n=0;
    int i;
    double m = 0.1;
    for ( i = 1;s!=0; i++)
    {
        
        if (s % 2 == 1)
        {
            m *= 10;
            k=s% 10;28             s=s/10;
            n += m*k;
        }
        else
        {
            s /= 10;
        }
    }
    return n;
}

 实验7

#include<stdio.h>
void main()
{
    int a[10], x, i, j, k, b;
    x = 0;
    while (1)
    {
        x++;
        b = 1;
        for (i = 0; i < 10; i++)
        {
            a[i] = 0;
        }
        k = x * x;
        while (k)
        {
            j = k % 10;
            a[j]++;
            if (a[j] > 1)
            {
                b = 0;
                break;
            }
            k /= 10;
        }
        if (b == 0)
            continue;
        k = x * x * x;
        while (k)
        {
            j = k % 10; a[j]++;
            if (a[j] > 1)
            {
                b = 0;
                break;
            }
            k /= 10;
        }
        if (b == 0)
            continue;
        for (i = 0; i < 10; i++)
        {
            if (a[i] != 1)
            {
                b = 0;
                break;
            }
            if (b)
            {
                printf("[%d,%d,%d]\n", x, x * x, x * x * x);
                break;
            }
        }
    }
}