table1:
a_id a1 a2 a3
1 d d d
2 e e e
3 f f f
table2:
b_id a_id b1 b2
1 2 s s
2 2 c c
3 3 h h
4 3 n n
5 3 r r
要达到的结果:
a_id a1 a2 a3 数量(别名)
1 d d d 0
2 e e e 2
3 f f f 3
解决方法:![]()
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declare @b1 table(a_ID INT,a1 varchar(10),a2 varchar(10),a3 varchar(10))
insert into @b1
select 1,'d','d','d' union
select 2,'e','e','e' union
select 3, 'f','f','f'
declare @b2 table(b_ID INT,a_id int,b1 varchar(10),b2 varchar(10))
insert into @b2
select 1,'2','s','s' union
select 2,'2','c','c' union
select 3,'3','h','h' union
select 4,'3','n','n' union
select 5,'3','r','r'
select a.a_id,a.a1,a.a2,a.a3,数量=(select count(b.a_id) from @b2 b where a_id=a.a_id) from @b1 a
--测试结果:
-- a_id a1 a2 a3 数量
-- 1 d d d 0
-- 2 e e e 2
--3 f f f 3
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