实验5
task1.1
#include <stdio.h> #define N 4 int main(){ int x[N] = {1,9,8,4}; int i; int *p; for(i = 0; i < N; i++) printf("%d", x[i]); printf("\n"); for(p = x; p < x + N; ++p) printf("%d", *p); printf("\n"); p = x; for(i = 0; i < N; ++i) printf("%d", p[i]); printf("\n"); return 0; }

task1.2
#include <stdio.h> int main(){ int x[2][4] = {{1,9,8,4}, {2,0,4,9}}; int i, j; int *p; int(*q)[4]; for(i = 0; i < 2; ++i){ for(j = 0; j < 4; ++j) printf("%d", x[i][j]); printf("\n"); } for(p = &x[0][0], i = 0; p < &x[0][0] + 8; ++p, ++i){ printf("%d", *p); if((i + 1) % 4 == 0) printf("\n"); } for(q = x; q < x + 2; ++q){ for(j = 0; j < 4; ++j) printf("%d", *(*q + j)); printf("\n"); } return 0; }

task2.1
#include <stdio.h> #include <string.h> #define N 80 int main() { char s1[] = "Learning makes me happy"; char s2[] = "Learning makes me sleepy"; char tmp[N]; printf("sizeof(s1) vs. strlen(s1): \n"); printf("sizeof(s1) = %d\n", sizeof(s1)); printf("strlen(s1) = %d\n", strlen(s1)); printf("\nbefore swap: \n"); printf("s1: %s\n", s1); printf("s2: %s\n", s2); printf("\nswapping...\n"); strcpy(tmp, s1); strcpy(s1, s2); strcpy(s2, tmp); printf("\nafter swap: \n"); printf("s1: %s\n", s1); printf("s2: %s\n", s2); return 0; }

1.数组s1的大小是24;sizeof(s1)计算内存占用;strlen(s1)统计字符串长度
2.不能,该写法为常量
3.是
task2.2
#include <stdio.h> #include <string.h> #define N 80 int main() { char *s1 = "Learning makes me happy"; char *s2 = "Learning makes me sleepy"; char *tmp; printf("sizeof(s1) vs. strlen(s1): \n"); printf("sizeof(s1) = %d\n", sizeof(s1)); printf("strlen(s1) = %d\n", strlen(s1)); printf("\nbefore swap: \n"); printf("s1: %s\n", s1); printf("s2: %s\n", s2); printf("\nswapping...\n"); tmp = s1; s1 = s2; s2 = tmp; printf("\nafter swap: \n"); printf("s1: %s\n", s1); printf("s2: %s\n", s2); return 0; }

1.它的地址,该地址内存占用,该地址字符串长度
2.可以,此为指针变量,task1为常量
3.交换的是地址,没有
task3
#include <stdio.h> void str_cpy(char *target, const char *source); void str_cat(char *str1, char *str2); int main() { char s1[80], s2[20] = "1984"; str_cpy(s1, s2); puts(s1); str_cat(s1, " Animal Farm"); puts(s1); return 0; } void str_cpy(char *target, const char *source) { while(*target++ = *source++); } void str_cat(char *str1, char *str2) { while(*str1) str1++; while(*str1++ = *str2++); }

task4
#include <stdio.h> #define N 80 int func(char *); int main() { char str[80]; while(gets(str) != NULL) { if(func(str)) printf("yes\n"); else printf("no\n"); } return 0; } int func(char *str) { char *begin, *end; begin = end = str; while(*end) end++; end--; while(begin < end) { if(*begin != *end) return 0; else { begin++; end--; } } return 1; }

task5
#include <stdio.h> #define N 80 void func(char *); int main() { char s[N]; while(scanf("%s", s) != EOF) { func(s); puts(s); } return 0; } void func(char *str) { int i; char *p1, *p2, *p; p1 = str; while(*p1 == '*') p1++; p2 = str; while(*p2) p2++; p2--; while(*p2 == '*') p2--; p = str; i = 0; while(p < p1) { str[i] = *p; p++; i++; } while(p <= p2) { if(*p != '*') { str[i] = *p; i++; } p++; } while(*p != '\0') { str[i] = *p; p++; i++; } str[i] = '\0'; }

task6.1
#include <stdio.h> #include <string.h> void sort(char *name[], int n); int main() { char *course[4] = {"C Program", "C++ Obeject Oriented Program", "Operating System", "Date Structure and Algorithms"}; int i; sort(course, 4); for(i = 0; i < 4; i++) printf("%s\n", course[i]); return 0; } void sort(char *name[], int n) { int i, j; char *tmp; for(i = 0; i < n-1; ++i) for(j = 0; j < n-1-i; ++j) if(strcmp(name[j], name[j + 1]) > 0) { tmp = name[j]; name[j] = name[j + 1]; name[j + 1] = tmp; } }

task6.2
#include <stdio.h> #include <string.h> void sort(char *name[], int n); int main() { char *course[4] = {"C Program", "C++ Obeject Oriented Program", "Operating System", "Date Structure and Algorithms"}; int i; sort(course, 4); for(i = 0; i < 4; i++) printf("%s\n", course[i]); return 0; } void sort(char *name[], int n) { int i, j, k; char *tmp; for(i = 0; i < n-1; ++i) { k = i; for(j = i + 1; j < n; j++) if(strcmp(name[j], name[k]) < 0) k = j; if(k != i) { tmp = name[j]; name[i] = name[k]; name[k] = tmp; } } }

内存中字符串的存储位置发生了交换
task7
#include <stdio.h> #include <string.h> #define N 5 int check_id(char *str); int main() { char *pid[N] = {"31010120000721656X", "330106199609203301", "53010220051126571", "510104199211197977", "53010220051126133Y"}; int i; for(i = 0; i < N; ++i) if(check_id(pid[i])) printf("%s\tTrue\n", pid[i]); else printf("%s\tFalse\n", pid[i]); return 0; } int check_id(char *str) { char *p = str; while(*p >= '0' && *p <= '9' || *p == 'X') p++; if(*p == '\0'&& strlen(str) == 18) return 1; else return 0; }

task8
#include <stdio.h> #define N 80 void encoder(char *s); void decoder(char *s); int main() { char words[N]; printf("输入英文文本:"); gets(words); printf("编码后的英文文本:"); encoder(words); printf("%s\n", words); printf("对编码后的英文文本解码:"); decoder(words); printf("%s\n", words); return 0; } void encoder(char *s) { while(*s!='\0') if(*s >= 'a' && *s <= 'z' || *s >= 'A' && *s <= 'Z') { *s = *s + 1; *s++;} else if(*s == 'z'||*s == 'Z') { *s = *s - 25; *s++;} else s++; } void decoder(char *s) { while(*s!='\0') if(*s >= 'a' && *s <= 'z' || *s >= 'A' && *s <= 'Z') { *s = *s - 1; *s++;} else if(*s == 'a'||*s == 'A') { *s = *s + 25; *s++;} else s++; }

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