HDU - 2051 Bitset

题目

Give you a number on base ten,you should output it on base two.(0 < n < 1000)
Input
For each case there is a postive number n on base ten, end of file.
Output
For each case output a number on base two.
Sample Input
1
2
3
Sample Output
1
10
11

思路

输入一个十进制数，输出一个二进制数。
rt，我果断想到了java中的toBinaryString();
不过，相比而言，用c实现较麻烦！

java代码

import java.util.Scanner;
public class Main{
    public static void main(String[] args){
        Scanner it=new Scanner(System.in);
        while(it.hasNext()){
            int n = it.nextInt();
            System.out.println(Integer.toBinaryString(n));
        }
    }
}

c代码

#include<stdio.h>
int main(){
    int n;
    while(scanf(" %d",&n)!=EOF){
        int a[12];
        for(int i=0;n>0;i++){
            if(n%2==0)a[i]=2;
            else a[i]=1;
            n=n/2;
        }
        for(int i=12;i>=0;i--){
        if(a[i]==2)printf("0");
        if(a[i]==1)printf("1");
        }
        printf("\n");
    }
    return 0;
}

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