python字符串之间的相似度比较

import difflib

a= "[instance: *] VM * (Lifecycle Event)"
c= "[instance: *] VM Resumed (Lifecycle Event)"


print(difflib.SequenceMatcher(None,a,c).ratio())

#0.9052631578947369



python有较全的库来自动比较,很方便
posted @ 2021-08-10 09:18  学习呀!  阅读(458)  评论(0)    收藏  举报