集合的方法 

 1 #set是可变的数据类型，里面的元素是不可变的,无序，不重复
 2 # set1 = {1, 'str', False, (1, 2, 3), 1, 1}
 3 # print(set1)
 4 
 5 #增add
 6 # set1 = {'chuan', 'huang', 'lin', 'li'}
 7 # set1.add('liu')
 8 # print(set1)
 9 #
10 # #update迭代元素的更新
11 # set1.update('abc')
12 # print(set1)
13 
14 
15 #删
16 # set1 = {'chuan', 'huang', 'lin', 'li'}
17 # print(set1.pop())
18 # print(set1)
19 #
20 # set1.remove('huang')        #按元素去删
21 # print(set1)
22 #
23 # set1.clear()                #清空
24 # del set1                    #删除
25 
26 
27 #查
28 # set1 = {'chuan', 'huang', 'lin', 'li'}
29 # for i in set1:
30 #     print(i)
31 
32 #集合的并集
33 # set1 = {1,2,3,4}
34 # set2 = {3,4,5,6}
35 # set3 = set1 & set2
36 # print(set3)           #{3, 4}
37 # print(set1.intersection(set2))    #{3, 4}
38 
39 
40 #集合的交集
41 # set1 = {1,2,3,4}
42 # set2 = {3,4,5,6}
43 # set3 = set1 | set2
44 # print(set3)           #{1, 2, 3, 4, 5, 6}
45 # print(set1.union(set2))    #{1, 2, 3, 4, 5, 6}
46 
47 #反交集
48 # set1 = {1,2,3,4}
49 # set2 = {3,4,5,6}
50 # print(set1 ^ set2)           #{1, 2, 5, 6}
51 # print(set1.symmetric_difference(set2))       #{1, 2, 5, 6}
52 
53 #差集，set1和set2去除相同部分而剩下的元素
54 # set1 = {1,2,3,4}
55 # set2 = {3,4,5,6}
56 # print(set1 - set2)     #{1，2}
57 # print(set1.difference(set2))      #{1，2}
58 
59 #超集和子集
60 # set1 = {1,2,3,4}
61 # set2 = {1,2,3,4,5,6}
62 # print(set1 < set2)
63 # print(set1.issubset(set2))
64 # print(set2 > set1)
65 # print(set2.issuperset(set1))
66 
67 #去除相同的元素
68 # li = [1,55,6,2,3,4,6,6,3]
69 # set1 = set(li)
70 # print(set1)
71 # li = list(set1)
72 # print(li)
73 
74 
75 #转换为不可变数据类型
76 # set2 = frozenset('abcd')
77 # print(set2, type(set2))

 

posted @ 2018-08-19 23:00  该搬砖啦  阅读(139)  评论(0)    收藏  举报