试验任务6
实验1：
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#include <stdio.h>
#include <string.h>
#define N 3
typedef struct student
{
int id;
char name[20];
char subject[20];
double perf;
double mid;
double final;
double total;
char level[10];
} STU;
void input(STU [],int);
void output(STU [],int);
void calc(STU [],int);
int fail(STU [],STU [],int);
void sort(STU [],int);
int main()
{
STU st[N],fst[N];
int k;
printf("录入学生成绩信息：\n");
input(st,N);
printf("\n成绩处理...\n");
calc(st,N);
k = fail(st, fst, N);
sort(st,N);
printf("\n学生成绩排名情况:\n");
output(st,N);
printf("\n不及格学生信息：\n");
output(fst,k);
return 0;
}
void input(STU s[],int n)
{
int i;
for(i = 0;i<n;i++)
{
scanf("%d %s %s %lf %lf %lf",&s[i].id,s[i].name,s[i].subject,
&s[i].perf,&s[i].mid,&s[i].final);
}
}
void output(STU s[],int n)
{
int i;
printf("--------\n");
printf("学号 姓名 科目 平时 期中 期末 总评 等级\n");
for(i = 0;i<n;i++)
{
printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",
s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level);
}
}
void calc(STU s[],int n)
{
int i;
for(i = 0;i<n;i++)
{
s[i].total = s[i].perf*0.2 + s[i].mid*0.2 + s[i].final*0.6;
if(s[i].total >= 90)
strcpy(s[i].level,"优");
else if(s[i].total >= 80)
strcpy(s[i].level,"良");
else if(s[i].total >= 70)
strcpy(s[i].level,"中");
else if(s[i].total >= 60)
strcpy(s[i].level,"及格");
else
strcpy(s[i].level,"不及格");
}
}
int fail(STU s[],STU t[],int n)
{
int i,cnt = 0;
for(i = 0;i<n;i++)
{
if(s[i].total < 60)
t[cnt++] = s[i];
}
return cnt;
}
void sort(STU s[],int n)
{
int i,j;
STU t;
for(i = 0;i<n-1;i++)
for(j = 0;j<n-1-i;j++)
if(s[j].total < s[j+1].total)
{
t = s[j];
s[j] = s[j + 1];
s[j+1] = t;
}
}
实验任务2：
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#include <stdio.h>
#include <string.h>
#define N 10
#define M 80
typedef struct
{
char name[M];
char author[M];
}Book;
int main()
{
Book x[N] = {
{"《一九八四》","乔治.奥威尔"},
{"《美丽新世界》","赫胥黎"},
{"《昨日的世界》","斯蒂芬.茨威格"},
{"《万历十五年》","黄仁宇"},
{"《一只特立独行的猪》","王小波"},
{"《百年孤独》","马尔克斯"},
{"《查令十字街84号》","海莲.汉芙"},
{"《只是孩子》","帕蒂.史密斯"},
{"《刀锋》","毛姆"},
{"《沉默大多数》","王小波"},
};
Book *ptr;
int i;
char author[M];
int found;
printf("--------所有图书信息----------\n");
for(ptr = x;ptr < x + N;++ptr)
printf("%-30s%-30s\n",ptr->name,ptr->author);
printf("\n--------按作者查询图书----------\n");
printf("输入作者名：");
gets(author);
found = 0;
for(ptr = x;ptr<x+N;++ptr)
{
if(strcmp(ptr->author,author) == 0)
{
found = 1;
printf("%-30s%-30s\n",ptr->name,ptr->author);
}
}
if(!found)
printf("暂未收录该作者的书籍");
return 0;
}
试验任务3：
task3.1
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#include <stdio.h>
#include <stdlib.h>
#define N 80
typedef struct Filminfo{
char name[N];
char director[N];
char region[N];
int year;
struct Filminfo *next;
}Film;
void output(Film *head);
Film *insert(Film *head,int n);
int main()
{
int n;
Film *head;
head = NULL;
printf("输入影片数目:");
scanf("%d",&n);
head = insert(head,n);
printf("\n所有影片信息如下:\n");
output(head);
return 0;
}
Film *insert(Film *head,int n)
{
int i;
Film *p;
for(i = 1;i<=n;++i)
{
p = (Film *)malloc(sizeof(Film));
printf("请输入第%d部影片信息：",i);
scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
p->next = head;
head = p;
}
return head;
}
void output(Film *head)
{
Film *p;
p = head;
while(p != NULL)
{
printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
p = p -> next;
}
}
****
task3.2
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#include <stdio.h>
#include <stdlib.h>
#define N 80
typedef struct Filminfo{
char name[N];
char director[N];
char region[N];
int year;
struct Filminfo *next;
}Film;
void output(Film *head);
Film *insert(Film *head,int n);
int main()
{
int n;
Film *head;
Film *p;
p = (Film *)malloc(sizeof(Film));
p->next = NULL;
head = p;
printf("输入影片数目:");
scanf("%d",&n);
head = insert(head,n);
printf("\n所有影片信息如下:\n");
output(head);
return 0;
}
Film *insert(Film *head,int n)
{
int i;
Film *p;
for(i = 1;i<=n;++i)
{
p = (Film *)malloc(sizeof(Film));
printf("请输入第%d部影片信息：",i);
scanf("%s %s %s %d",p->name,p->director,p->region,&p->year);
p->next = head->next;
head->next = p;
}
return head;
}
void output(Film *head)
{
Film *p;
p = head->next;
while(p != NULL)
{
printf("%-20s %-20s %-20s %d\n",p->name,p->director,p->region,p->year);
p = p -> next;
}
}
实验任务4：
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#include <stdio.h>
#define N 10
typedef struct {
char isbn[20];
char name[80];
char author[80];
double sales_price;
int sales_count;
} Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
{"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
{"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
{"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
{"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
{"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
{"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
{"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
{"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
printf("图书销量排名(按销售册数): \n");
sort(x, N);
output(x, N);
printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
return 0;
}
void output(Book x[], int n)
{
int i;
int a = 0;
for(i = 0;x[i].sales_count != 0;i++)
a++;
for(i = 0;i<a;i++)
{
printf("%s %s %s %lf %d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}
}
void sort(Book x[],int n)
{
Book a;
int i,j;
printf("ISBN号 书名 作者 售价 销售册数\n");
for(i = 0;i<n;i++)
{
for(j = 0;j<n-1;j++)
{
if(x[j].sales_count < x[j+1].sales_count)
{
a = x[j];
x[j] = x[j+1];
x[j+1] = a;
}
}
}
}
double sales_amount(Book x[], int n)
{
double all,total,a,b;
int i;
for(i = 0;i<n;i++)
{
a = x[i].sales_count;
b = x[i].sales_price;
total = a*b;
all += total;
}
return all;
}
试验任务5：
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#include <stdio.h>
typedef struct {
int year;
int month;
int day;
} Date;
// 函数声明
void input(Date *pd); // 输入日期给pd指向的Date变量
int day_of_year(Date d); // 返回日期d是这一年的第多少天
int compare_dates(Date d1, Date d2); // 比较两个日期:
// 如果d1在d2之前，返回-1;
// 如果d1在d2之后，返回1
// 如果d1和d2相同，返回0
void test1() {
Date d;
int i;
printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
}
}
void test2() {
Date Alice_birth, Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if(ans == 0)
printf("Alice和Bob一样大\n\n");
else if(ans == -1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main() {
printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
test1();
printf("\n测试2: 两个人年龄大小关系\n");
test2();
}
void input(Date *pd)
{
scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}
int day_of_year(Date d)
{
int a[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
int i,j,total;
total = 0;
if((d.year % 4 == 0 && d.year %100 != 0) || d.year % 400 == 0)
a[1] = 29;
for(i = 0;i < 12;i++)
{
if(d.month == 1)
{
total = d.day;
break;
}
else
{
j = a[i];
total += j;
if(d.month == i + 2)
{
total += d.day;
break;
}
}
}
return total;
}
int compare_dates(Date d1, Date d2)
{
if(d1.year > d2.year)
return 1;
if(d1.year < d2.year)
return -1;
if(d1.year == d2.year)
{
if(day_of_year(d1) == day_of_year(d2))
return 0;
if(day_of_year(d1) > day_of_year(d2))
return 1;
if(day_of_year(d1) < day_of_year(d2))
return -1;
}
}
试验任务6：
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#include <stdio.h>
#include <string.h>
enum Role {admin, student, teacher};
typedef struct {
char username[20];
char password[20];
enum Role type;
} Account;
void output(Account x[], int n);
int main() {
Account x[] = {{"A1001", "123456", student},
{"A1002", "123abcdef", student},
{"A1009", "xyz12121", student},
{"X1009", "9213071x", admin},
{"C11553", "129dfg32k", teacher},
{"X3005", "921kfmg917", student}};
int n;
n = sizeof(x)/sizeof(Account);
output(x, n);
return 0;
}
void output(Account x[], int n)
{
int i,j,a;
a = 0;
for(i = 0;i<n;i++)
{
printf("%s\t",x[i].username);
a = strlen(x[i].password);
for(j = 0;j<a;j++)
{
printf("*");
}
printf("\t\t\t");
switch(x[i].type)
{
case 0:printf("admin");break;
case 1:printf("student");break;
case 2:printf("teacher");break;
}
printf("\n");
}
}
试验任务7：
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#include <stdio.h>
#include <string.h>
typedef struct {
char name[20];
char phone[12];
int vip;
} Contact;
void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);
#define N 10
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息: \n");
output(list, N);
printf("\n输入要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; ++i) {
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
void set_vip_contact(Contact x[], int n, char name[])
{
int i;
for(i = 0;i<n;i++)
{
if(strcmp(x[i].name,name) == 0)
x[i].vip = 1;
}
}
void display(Contact x[], int n)
{
int i,j;
Contact a;
for(i = 0;i<n;i++)
{
for(j = 0;j < n-1;j++)
{
if(x[j].vip < x[j+1].vip)
{
a = x[j];
x[j] = x[j+1];
x[j+1] = a;
}
if(x[j].vip == x[j + 1].vip)
{
if(strcmp(x[j].name,x[j+1].name) >= 0)
{
a = x[j];
x[j] = x[j+1];
x[j+1] = a;
}
}
}
}
for(i = 0;i<n;i++)
{
printf("%s\t\t%s",x[i].name,x[i].phone);
if(x[i].vip == 1)
{
printf("\t\t*");
}
printf("\n");
}
}
void output(Contact x[], int n) {
int i;
for(i = 0; i < n; ++i) {
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip)
printf("%5s", "*");
printf("\n");
}
}
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