leetcode 48 旋转图像 rotate-image【ct】

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思路:

1. 对角线翻折  

  i = 0 ; i<matrix.length

  j = i ; j < matrix.length

    matrix[i][j] matrix[j][i]  =  matrix[j][i] matrix[i][j]

2. 左右翻折

  i = 0 i<matrix.length

  j = 0 j < Math.floor(matrix.length/2)

    matrix[i][j] matrix[i][matrix.length-1-j] =  matrix[i][matrix.length-i-j] matrix[i][j]

 

 

posted @ 2023-06-18 20:24  hh9515  阅读(16)  评论(0)    收藏  举报